tf.math.is_strictly_increasing

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Returns True if x is strictly increasing.

Aliases:

• tf.compat.v1.debugging.is_strictly_increasing
• tf.compat.v1.is_strictly_increasing
• tf.compat.v1.math.is_strictly_increasing
• tf.compat.v2.math.is_strictly_increasing
• tf.debugging.is_strictly_increasing
• tf.is_strictly_increasing

tf.math.is_strictly_increasing(
    x,
    name=None
)

Elements of x are compared in row-major order. The tensor [x[0],...] is strictly increasing if for every adjacent pair we have x[i] < x[i+1]. If x has less than two elements, it is trivially strictly increasing.

See also: is_non_decreasing

Args:

• x: Numeric Tensor.
• name: A name for this operation (optional). Defaults to "is_strictly_increasing"

Returns:

Boolean Tensor, equal to True iff x is strictly increasing.

Raises:

• TypeError: if x is not a numeric tensor.